Phys 0175 - Worksheet _8 Solution

# Phys 0175 - Worksheet _8 Solution - PHYS 0175 S rin 2008...

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Unformatted text preview: PHYS 0175 S rin 2008 — Worksheet Problem Set #8 Part A Your Name: ‘ K CC {4 lg! TA: Score: The diagram below shows an electron that has been accelerated from rest through potential difference V1=750 V entering the gap between two parallel, ﬂat metal plates that have a spacing d=20.0 mm and a potential difference V2=375 V between them. (The lower plate is at the lower potential.) Neglect all fringing effects and assume that the electron’s velocity vector is perpendicular to the electric ﬁeld vector between the plates. . . _ . 9-!) (1) What IS the electron’s kinetic energy after passmg _-_-. z ( ) through potential difference V1? Q‘Vl (0 :. lpwx I (2) What is the electron’s speed when it enters the region between the plates where it experiences both an electric force and a magnetic force? ? KE: lamang ==> '5": if = HMO "/5 C (m: 9.109xto'glkg> (3) What are the magnitude and direction of the elect force on the electron? V 2. ’5’ , , . Ft: guE : 3e, 1...: 3,00xlo’ N in Pas. yvdu’tdwu A . n o a (4) Therefore, what must be the magnitude and direction of the magnetic force on the electron? F3 .~_ 3_oa xm'tr/V do. M63. y—dc'ycmlt’ou. (5) What are the magnitude and direction of the magnetic ﬁeld that will produce that magnetic force on the electron? -— #— Tj: 1a¢1r35c..t9o"--_—> 3= #3; : (. XlohsT—r V13 Mus'i' you’d: incl-p {2454; (Mejiadhzmi PHYS 0175 S rin 2008 —Worksheet Problem Set #8 PartB Your Name: Kc9£ (’1 (er Score: The circuit shown in the diagram below is used to make a magnetic balance to weigh objects. The mass m to be weighed is suspended from the center of the bar, which is placed in a uniform magnetic ﬁeld of magnitude B=0.75O T and directed into the plane of the diagram. The battery voltage can be adjusted to change the current I in the circuit. The horizontal bar has length L=0.400 m and negligible mass. It is electrically connected to the circuit by thin vertical wires that can support no appreciable tension; all of the weight of the suspended mass m is assumed to be supported by the magnetic force on the bar. A resistor R=5.00 Q is in series with the bar; the resistance of the rest of the circuit is negligible. The maximum terminal voltage of the battery is Vab=225 V. (1) What is the expression for the magnitude of the force that a ..—- , magnetic ﬁeld exerts on a current-carrying conductor of F = .L Slkg’ length L? In this problem, what is the angle between the magnetic ﬁeld and the direction of the current? 6 ._. 90' (2) What must be the magnitude and direction of the magnetic force on the barto support a mass m? F5 = mg upward #5::th Wt ) (3) From the information given, what will be the maximum ? current passing through the bar? L/ .— __ 2 V ..L “ - 2 5’ = trams, ’— my T” 52044, (4) Thus what maximum mass m can be weighed? T . - Mug: I'm/(.3 2; wk“: :‘1‘:Lyn—15—=Ls“z (5) In what direction must the current ﬂow to produce a magnetic force in the direction you determined in (2) above? Can/elf!" mus? Flaw Hargqu Ha: In!“ 60M [cf/T {'0 YL'SILH‘. My answers are: ...
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Phys 0175 - Worksheet _8 Solution - PHYS 0175 S rin 2008...

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