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Unformatted text preview: H = k copper A (T M T C )/L copper The rate of heat transfer is the same in both bars From these two equations we can get T M = 20.7 o C After we know the value of T M we can get H = 15.9 Watts Cross sectional area A = 0.0004 m 2 H H...
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This note was uploaded on 04/18/2008 for the course PHYS 116a taught by Professor Maguire during the Spring '08 term at Vanderbilt.
 Spring '08
 Maguire
 Physics, Conductivity, Heat

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