pre-lecture notes 1-13 - ELEN 557 802.11n has MIMO The...

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ELEN 557 01-13-2011 802.11n has MIMO The notation helps identify what a given radio is capable of. The first number ( a ) is the maximum number of transmit antennas or RF chains that can be used by the radio. The second number ( b ) is the maximum number of receive antennas or RF chains that can be used by the radio. The third number ( c ) is the maximum number of data spatial streams the radio can use. For example, a radio that can transmit on two antennas and receive on three, but can only send or receive two data streams would be . The 802.11n draft allows up to . Common configurations of 11n devices are , , and . All three configurations have the same maximum throughputs and features, and differ only in the amount of diversity the antenna systems provide. In addition, a fourth configuration, is becoming common, which has a higher throughput, due to the additional data stream. MCS Index Spatial Streams Modulation Type Coding Rate Data Rate Mb/s 20 MHz channel 40 MHz channel 800ns GI 400ns GI 800ns GI 400ns GI 0 1 BPSK 1/2 6.50 7.20 13.50 15.00 1 1 QPSK 1/2 13.00 14.40 27.00 30.00 2 1 QPSK 3/4 19.50 21.70 40.50 45.00 3 1 16- QAM 1/2 26.00 28.90 54.00 60.00 4 1 16- QAM 3/4 39.00 43.30 81.00 90.00 5 1 64- QAM 2/3 52.00 57.80 108.00 120.00 6 1 64- QAM 3/4 58.50 65.00 121.50 135.00 7 1 64- QAM 5/6 65.00 72.20 135.00 150.00 8 2 BPSK 1/2 13.00 14.40 27.00 30.00 9 2 QPSK 1/2 26.00 28.90 54.00 60.00 10 2 QPSK 3/4 39.00 43.30 81.00 90.00 11 2 16- QAM 1/2 52.00 57.80 108.00 120.00 12 2 16- QAM 3/4 78.00 86.70 162.00 180.00 13 2 64- QAM 2/3 104.00 115.60 216.00 240.00 14 2 64- QAM 3/4 117.00 130.00 243.00 270.00 15 2 64- QAM 5/6 130.00 144.40 270.00 300.00 Page 1
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ELEN 557 01-13-2011 16 3 BPSK 1/2 19.50 21.70 40.50 45.00 17 3 QPSK 1/2 39.00 43.30 81.00 90.00 18 3 QPSK 3/4 58.50 65.00 121.50 135.00 19 3 16- QAM 1/2 78.00 86.70 162.00 180.00 20 3 16- QAM 3/4 117.00 130.70 243.00 270.00 21 3 64- QAM 2/3 156.00 173.30 324.00 360.00 22 3 64- QAM 3/4 175.50 195.00 364.50 405.00 23 3 64- QAM 5/6 195.00 216.70 405.00 450.00 ... 4 ... ... ... ... ... ... 31 4 64- QAM 5/6 260.00 288.90 540.00 600.00 40 MHz 1/(40 10^6) 1/40000000 N[%] 2.5×10 -8 % /10^(-9) 25. ok T = 25 nsec, so 400 nsec GI must be per frame (not per symbol) they don' t tell us the frame width, but we can calculate/estimate it: 6/(25 10^(-9)) 240000000 that' s the data rate per antenna 240 4 960 that' s Mb/s if I use all 4 of them (and I can in 4 X 4:4 version of 802.11 n) % 5/6 800 that' s taking into account the coding (5 bits of info/6 bits sent) 600/800 3/4 Solve[(n 25)/(n 25+400)==3/4,n] {{n 48}} 48 25 Page 2
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ELEN 557 01-13-2011 1200 1200 nsec of info. (plus 400 nsec of GI) = 1 frame Hot news source: Page 3
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ELEN 557 01-13-2011 Page 4
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ELEN 557 01-13-2011 Comparisons of 4G and 3G 3G (including 2.5G, sub3G) 4G
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  • Fall '09
  • WiMAX, 3GPP Long Term Evolution, LTE network, ELEN, LTE service

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