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**Unformatted text preview: **23. The constant-acceleration condition permits the use of Table 2-1.
2 (a) Setting v = 0 and x0 = 0 in v 2 = v0 + 2a(x - x0 ), we find x=- 2 1 v0 1 =- 2 a 2 5.00 106 -1.25 1014 = 0.100 m . Since the muon is slowing, the initial velocity and the acceleration must have opposite signs. (b) Below are the time-plots of the position x and velocity v of the muon from the moment it enters the field to the time it stops. The computation in part (a) made no reference to t, so that other equations from Table 2-1 (such as v = v0 + at and x = v0 t + 1 at2 ) are used in making these plots. 2 10 7.5 5.0 2.5 0
....... ....... ....... ....... ..... ..... .... .... . .. .... ... ... ... ... ... ... ... ... ... ... ... ... . .. ... ... ... ... ... ... ... ... . .. .. .. .. .. .. .. .. .. .. .. .. .. .. .. .. . .. .. .. . .. .. .. . .. .. .. . .. . .. .. .. .. .. . .. .. .. . . 8.0 v (Mm/s) 6.0 4.0 2.0 0
... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... ... x (cm) 10 20 t (ns) 30 40 10 20 t (ns) 30 40 ...

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