p02_009

Fundamentals of Physics,Vol 1 (Chapters 1 - 20)

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9. Converting to seconds, the running times are t 1 = 147 . 95 s and t 2 = 148 . 15 s, respectively. If the runners were equally fast, then s avg 1 = s avg 2 = L 1 t 1 = L 2 t 2 . From this we obtain L 2 L 1 = µ 148 . 15 147 . 95 1 L 1 1 . 35 m where we set L 1 1000 m in the last step. Thus, if
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Unformatted text preview: L 1 and L 2 are no di±erent than about 1 . 35 m, then runner 1 is indeed faster than runner 2. However, if L 1 is shorter than L 2 than 1 . 4 m then runner 2 is actually the faster....
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