6.(a) Using the fact that time = distance/velocity while the velocity is constant, we Fndvavg=73.2m+73.2m73.1.22 m/s+73.3.05 m=1.74 m/s.(b) Using the fact that distance =vtwhile the velocityvis constant, we Fndvavg=(1.22 m/s)(60 s) + (3.05 m/s)(60 s)120 s=2.14 m/s.(c) The graphs are shown below (with meters and seconds understood). The Frst consists of two (solid)line segments, the Frst having a slope of 1.22 and the second having a slope of 3.05. The slope ofthe dashed line represents the average velocity (in both graphs). The second graph also consists oftwo (solid) line segments, having the same slopes as before – the main di±erence (compared to theFrst graph) being that the stage involving higher-speed motion lasts much longer.
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