p02_050

Fundamentals of Physics,Vol 1 (Chapters 1 - 20)

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50. With + y upward, we have y 0 =36 . 6mand y =12 . 2 m. Therefore, using Eq. 2-18 (the last equation in Table 2-1), we Fnd y y 0 = vt + 1 2 gt 2 = v = 22 m / s at t =2
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Unformatted text preview: . 00 s. The term speed refers to the magnitude of the velocity vector, so the answer is | v | = 22 . 0 m/s....
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This document was uploaded on 04/18/2008.

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