41. We neglect air resistance, which justifes settinga=−g=−9.8m/s2(takingdownas the−ydirection)For the duration oF the Fall. This is constant acceleration motion, which justifes the use oF Table 2-1(with ∆yreplacing ∆x).(a) Starting the clock at the moment the wrench is dropped (vo= 0), thenv2=v2o−2g∆yleads to∆y=−(−24)22(9.8)=−29.4mso that it Fell through a height oF 29..(b) Solvingv=v0−gtFor time, we fnd:t=v0−vg=0−(−24)9.8=2.45 s.(c) SI units are used in the graphs, and the initial position is taken as the coordinate origin. Inthe interest oF saving space, we do not show the acceleration graph, which is a horizontal line at
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