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**Unformatted text preview: **02 v 02 x 1 − v 01 x 2 . Substituting x 1 = 56 . 7 m, v 01 = 80 . 5 km / h = 22 . 4 m / s, x 2 = 24 . 4 m and v 02 = 48 . 3 km / h = 13 . 4 m/s, we Fnd t r = 13 . 4 2 (56 . 7) − 22 . 4 2 (24 . 4) (22 . 4)(13 . 4)(13 . 4 − 22 . 4) = 0 . 74 s and a = − 1 2 (13 . 4)22 . 4 2 − (22 . 4)13 . 4 2 (13 . 4)(56 . 7) − (22 . 4)(24 . 4) = − 6 . 2 m / s 2 . The magnitude of the deceleration is therefore 6 . 2 m/s 2 . Although rounded o± values are displayed in the above substitutions, what we have input into our calculators are the “exact” values (such as v 02 = 161 12 m/s)....

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