p02_035

Fundamentals of Physics,Vol 1 (Chapters 1 - 20)

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35. The acceleration is constant and we may use the equations in Table 2-1. (a) Taking the frst point as coordinate origin and time to be zero when the car is there, we apply Eq. 2-17 (with SI units understood): x = 1 2 ( v + v 0 ) t = 1 2 (15 + v 0 )(6) . With x =60 . 0 m (which takes the direction oF motion as the + x direction) we solve For the initial velocity: v 0 =5 . 00 m/s. (b) Substituting v =1 5m / s , v 0 =5m / sand t =6sin t o a =( v v 0 ) /t (Eq. 2-11), we fnd a =1 . 67 m/s 2 . (c) Substituting v =0in v 2 = v 2 0 +2 ax and solving For x ,weobta in x = v 2 0 2 a = 5 2 2(1 . 67) = 7 . 50 m . (d) The graphs require computing the time when v = 0, in which case, we use v = v 0 + at 0 =0. Thus, t 0 = v 0 a = 5
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This document was uploaded on 04/18/2008.

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