{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Quiz 2 - Name SO‘WE‘I‘OVL NetID Show your work...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Name: SO‘WE‘I‘OVL NetID: Show your work clearly and box your final answers. Fill in your LAST NAME, INI- TIALS, and NETID on the answer sheet. This is VERSION (?). ke = 8.99 x 109 N - mZ/Cz, co = 8.85 x 10-12 02/N - m2, e = 1.60 x 10-19 C [10 points] A particle (m = 50 g, q = 5.0 110) is released from rest when it is 50 cm from a second particle (Q = —20 MC). Determine the magnitude of the initial ac eleration - 1 z x - c 5: “66¢ of the 50-g Particle. \Fe‘ 2 {e 101,13“ : (9.117110 Mama )(10 (106532";- ) (A) 4.1 m/s2 (B) 9.3 m/s2 ‘_ 3 60 N g (C) 15 m/s2 (D) 23 m/s2 _ ‘ (12136 m/s? (F) 48 m/s2 ate LE) = 3‘ 6°” = G 54 m 52 (H) 65 m/s2 m 0‘ °5 k3 ‘ «my (J) 88 m/s2 (K) 91 m/s2 (L) 96 m/s2 [Z] [10 points] A charge Q is placed on the :1: axis at a: = +4.0 m. A second charge q is located at the origin. If Q = +75 nC and q = —8.0 nC, what is the magnitude of the electric field on the y axis at y = +3.0 m? . (.8 nC) ’ (at z (A) 10 N c (13) 18 N/C G ,. I: 151116 g 5 (fifim (W n) 32 N/C p E: ’ ie “701— ° LT‘Z ”‘ /C F) 44 N/CE‘. (5 m) ( ( m) “C ’ ( Q 6.. :- EL me: E; (4;) =r 3 (1%) Lfi‘fi)‘ 83 ‘51: 11:;8 El}; 2: 11:33 x E11, ‘ E: 67719 ‘ a: 0%) 5'- 3 (%)(f¢r%) =[\?( ) (K) 72 N/C (L) 79 N/C e. g a.) s. 31.4 (1.11%) , EX: 3., .~ 2,, 4.33 “,3“ng '= 0.1 (’3 ‘1 ( IEI‘J‘TF“? : («11+ 0.? 191%) = (a.sb)(?xw’)('°") =- [E [10 points] A 12—nC charge is istr' uted uniformly along the y axis from y): 0 to y = 4 m. Which of the following integrals is correct for the a: component of the electric field at :1: = 2 m on the x axis? 4&3? JE 056 = 42 (:3) , P ‘ (1)216f04mé317, (8)108L4fi71 a: 4;: dE=£t3 r1445??- (C) 54 fo4 {$117! (D) 216 f: lewr U ‘ A d 1 (E) mafim—jfifi (F) 54f04—+,‘,‘¥7m JEH {4.1573 3,: - (0“...3 ”(‘1 4 ‘ . (c) 216 {0 (33:5,; (H) 108 {0 F355 _ g (amoww‘la 2 3:111:40" 4 (1)54fo 131% (J) 215fo m‘z’pfl purl?- 4 d 4 d ”M A} (K) 10810.7,ng (L) 5410mm E. z 542. a (94%) 3 (4+ PH2223—2008-SPRING-Q2—v? Page 1 of 1 ...
View Full Document

{[ snackBarMessage ]}