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Unformatted text preview: HW3 1. See enclosed circuit board. 2. 3-5.
Measured Voltage VL B eft attery V1 V2 V3 V4 V5 VR ight B attery (volts) 9.50 9.93 1.36 5.16 -4.67 -2.93 9.48 L L eft oop (K ) VL (+ eftB VL attery) (-V1) (+ V3) (+ V4) R ight L oop (K ) VL 9.50 -9.93 5.16 -4.67 (-V2) (-V3) (+ V5) (+VR ightB attery) discrepancy Node B(K L C) -0.001015 0.0013737 -0.00035 -1.36 -5.16 -2.93 9.48 0.03 discrepancy C urrent F rom O hm's L (amperes) aw I1 =V1/ 9780 0.001015 I2 =V2/ 990 0.001374 I3 =V3/ 14750 0.00035 I4 =V4/ 4610 -0.001013 I5 =V5/ 2150 -0.001363 Node A (K L C) (-I1) (+ I2) (-I3) 0.06 discrepancy 8.569E -06 (+ I3) (-I4) (+ I5) discrepancy 0.0003498 0.001013 -0.001363 5.5E -08 4. The discrepancy for Kirchhoff's Voltage Law for both loops was very small, the largest value being only 0.06V. This means that Kirchhoff's Voltage Law was proved correct by my circuit and voltage measurements. 5. For Ohm's Law, I calculated the current in amperes for each side of the circuit that intersected a node. I said that currents flowing into the node were negative and currents flowing out were positive. Using these standards, I added all values flowing in and out of each node and was pleased when my discrepancy turned out to be very small, almost 0 as it should be. My largest value was 8.569E-06. This means that my circuit and measurements also satisfied Ohm's Law. The tiny discrepancy could have been the result of the accuracy of the meter or the resistor's values not being as precise as possible. ...
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This homework help was uploaded on 04/19/2008 for the course ECE 1002 taught by Professor Moorhead during the Fall '07 term at Mississippi State.
- Fall '07