# hw4 - 0*I3 0*I4 1*I5 = 0-1*I1 1*I2-1*I3 0*I4 0*I5 = 0 These...

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HW4 1. 2. Ohm’s Law for each resistor: V1 = 9780*I1 V2 = 990*I2 V3 = 14750*I3 V4 = 4610*I4 V5 = 2150*I5 KVL for the left loop: 9.50 – V1 + V3 + V4 = 0 KVL for the right loop: 9.48 – V2 – V3 + V5 = 0 KCL for the left branch: I1 + I4 = 0 KCL for the right branch: I2 + I5 = 0 KCL at node A: -I1 + I2 – I3 = 0 3. Substitute Ohm’s Law into the two KVL equations: 9.50 – (9780*I1) + (14750*I3) + (4610*I4) = 0 9.48 – (990*I2) – (14750*I3) + (2150*I5) = 0

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Recall the 3 KCL equations: I1 + I4 = 0 I2 + I5 = 0 -I1 + I2 – I3 = 0 Rearrange these 5 equations for the 5 currents: -9780*I1 0*I2 14750*I3 4610*I4 0*I5 = - 9.50 0*I1 -990*I2 -14750*I3 0*I4 2150*I5 = - 9.48 1*I1 0*I2 0*I3 1*I4 0*I5 = 0 0*I1 1*I2

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Unformatted text preview: 0*I3 0*I4 1*I5 = 0-1*I1 1*I2-1*I3 0*I4 0*I5 = 0 These are 5 simultaneous linear algebraic equations in the 5 unknown currents: I1, I2, I3, I4, I5. 4. Write these equations in matrix form: AI = b .-97800----= - .-14750461000 990 14750021501001001001 11 100I1I2I3I4I5 9 50 . 9 48000 Write Ohm’s Law in matrix form: V1V2 = V3V4V5 9780000009900000014750000004610000002150I1I2I3I4I5 5. Enter the matrix A into Matlab: Enter matrix b into Matlab: Calculate current in Matlab: 6. Enter matrix R and calculate the voltages with Ohm’s Law: 7. Comparison of HW3 values of current and voltages with the calculated ones from HW4....
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hw4 - 0*I3 0*I4 1*I5 = 0-1*I1 1*I2-1*I3 0*I4 0*I5 = 0 These...

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