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Unformatted text preview: j ) = 1, expressible in form 8. (a) h[n] = ( [n-1] + [n-1] + [n-2] + [n-3]) (b) H(e j ) = e-j3 /2 [cos(1.5 ) + cos(0.5 )] (c) (d) y[n] = 5 + 3.076cos(0.2 n 0.3 ) (e) filter is length 4, so for n 3 9. y(t) = 10 + 6.152cos(200 t 0.3 ) 10. (a) y[n] = y 1 [n] because DC value is removed by filter (b) H(e j ) = 2/3e-j(3 /2- /2) sin(1.5 ) (c) see next page (c) (d) y[n] = 1/3x[n] 1/3x[n-3] 11. (a) y[n] = 10 + 9cos(0.2 n - /2) (b) at = 2 0.17: phase is wrapped to plot between [- ] at = : amplitude of H(e j ) changes sign, therefore phase jump...
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This homework help was uploaded on 10/10/2007 for the course ECE 2200 taught by Professor Johnson during the Spring '05 term at Cornell University (Engineering School).
- Spring '05