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CO72_Mid_Term_Exam_3_Practice_3

# CO72_Mid_Term_Exam_3_Practice_3 - CO72 Midterm Exam 3...

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CO72 Midterm Exam 3 Practice Exam v.3 Temple University General Chemistry II Spring 2007 JP. Scovill G = H - T S G o = H o - T S o K eq = exp - G o /RT k = exp - G / RT G o = -RT ln K eq R = 8.314472 J K -1 mol -1 ; 8.314472 kPa L K -1 mol -1 ; 0.08206 L atm K -1 mol -1 ; J = kg m 2 s -2 Pa = N m -2 N =kg m s -2 0 o C = 273.15 o K 1 1 1 1 2 1 1 3 ↓ 3 1 1 4 6 4 ↓ 1 1 5 10 10 5 1 ↓ 1 6 ↓ 15 20 15 6 1 1 7 21 35 35 21 7 1 1 8 28 56 70 56 28 8 1 1 9 36 84 126 126 84 36 9 1 1 10 45 120 210 252 210 120 45 10 1 1 11 55 165 330 462 462 330 165 55 11 1 1 12 66 220 495 792 924 792 495 220 66 12 1 1 13 78 286 715 1287 1716 1716 1287 715 286 78 13 1 1 14 91 364 1001 2002 3003 3432 3003 2002 1001 364 91 14 1 1 15 105 455 1365 3003 5005 6435 6435 5005 3003 1365 455 105 15 1 1 16 120 560 1820 4368 8008 11440 12870 11440 8008 4368 1820 560 120 16 1

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1. (10) Acetic acid, CH 3 CO 2 H, has a pK a of 4.76 at 25 o C. a. Provide a chemical equation for the ionization of acetic acid in water. b. Calculate G o for the reaction you provided above. 2. (30) Provide a sketch for the titration of 1.00 M acetic acid with as a function of .addition of sodium hydroxide. Acetic acid has a p K a of 4.76. a. Be sure to compute and plot the pH of the initial 1.00 M acetic acid solution. b. Be sure to compute and plot 10 points in the buffering region of the titration curve. c. Be sure to compute and plot the pH of the solution at the equivalence point. d. Be sure to compute and plot the pH of the solution when 1.05, 1.1, 1.2, and 1.3 molar equivalents of base have been added to the solution. e. Suppose that you have a solution of 1.00 M Na + CH 3 CO 2 - and add 0.001 mol NaOH to this solution. Calculate the pH of the resulting solution. 3. (10) Water has p K w = 14 at 25 o C. a. Calculate K w . b. Write an equation for the autoionization of water. c. Write the mass action expression for the autoionization of water. d.

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CO72_Mid_Term_Exam_3_Practice_3 - CO72 Midterm Exam 3...

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