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Unformatted text preview: the next bit is a 1, the first source symbol is a 3. If the length of the string of 0s is even, immediately following the 11 is odd, the first codeword must be 110 and the first source symbol must be 4; if the length of the string of 0s is even, the first source symbol is a 3. By repeating this argument, we can see that this code is uniquely decodable....
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 Spring '08
 Eisler

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