HW2_solution - PHYSICS 140A : ASSIGNMENT #2 SOLUTIONS...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: PHYSICS 140A : ASSIGNMENT #2 SOLUTIONS Problem 1. Solution: (a) As we know B V and B T , we can directly use: Pa V RT P B B B 6 10 04 . 1 ! = = " (b) We can compute the area under the curve to get the work in this process. ) ( C B B B A V V P PdV PdV W ! ! = = " " ) 1 ( B C B VB VA A V V RT dV V RT ! ! = " # # J V V V V RT B C A B B 3 10 64 . 2 1 ln ! = " # $ % & ’ + ( ) ) * + , ,- . = / (c) ! ! ! + = = = " C B C B C B T PdV dE T Q d dS S (1) where 1 ! = " PV E , take it into (1), we get: P dP R V dV R dV T P T VdP PdV S C B C B ! ! " + " = + " + = # 1 1 ) 1 ( $ % % $ $ $ K J V V R B C / 3 . 40 ln 1 ! = " " # $ % % & ’ ! = ( ) ) Problem 2. Solution: First of all, let’s consider the work during this period, i.e. ABCD S ! ! ! ! + + + = = A D D C C B B A ABCD PdV PdV PdV PdV S W ! ! " + + = D C D A A D A B A A A V V P dV V V P dV V V P ) ( # # # # ) ( 1 1 ) ( 1 1 ! ! ! ! ! ! D A B A D A A V V V P V V P " " " " " = " Secondly, in this period, the ideal gas absorb heat during D->A, therefore:...
View Full Document

This note was uploaded on 02/06/2009 for the course PHYSICS 1101 taught by Professor Hasan during the Spring '08 term at Temple.

Page1 / 5

HW2_solution - PHYSICS 140A : ASSIGNMENT #2 SOLUTIONS...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online