exam1_solutions_60730 - KEY PHT .‘t‘l TK Sept-outlier...

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Unformatted text preview: KEY PHT .‘t‘l TK Sept-outlier ‘23. Eilfif‘l Name {printed}: Signature: Exam 1 Unique number fifl’FBG lustruetione: I NOTICE: For all! problems on this exam. you Should onetime g :. 1U 1113352. :"tleo. ignore nir emit-tuner: in till projeetile motion problems. a No notes, texthoohu, or eiu‘tiior fl-itlti are permitted. You tour utae u euleulotru'. a Use the. senntron answer elieet to provide the. :umwerfi. “Trim unti bubble your name and UT EID carefully. Sign {MEI date. it. Prior-k your scant-roll wire-J; u fit-2 pencil. a Any; question; you may have uhoul. the. text mtlel he diroeted to the instructor or "ll-1. no conversations onelfor collaborative work are permitted. Ir Home information that. may he useful 1:: provided on the lam. page of the: hundonr. 1{on may not nail: [mentions ubout. the inforrnution on thin; page. Also, it you detuel'l the page from the handout: you muse return it with the. reet of the handout at the end of the exmn. i Use the hook sides of the (noun pngee en; eerutch [Juper for culoulutione or: needed. a YOU IflUST TURN IN THIS DUEIPLETE EXAM HANDDUT {ALL PAGES, INCLUDING THE EQUATIDN SHEET} AT THE END DF EXAM. PRINT YUUIL HAl‘u’lfl AND ALSO SIGN THIS JJ'HUNT PAGE. 60750 i. 'I'er identirjn] hexea of 1113135 J'lf are. eunrnmtetl together by h Hiring. The. twn lmxt-EH are being pulled up a Irietienleee inclined plane. by a feree Ft as Shawn: with t'J‘JHHl'l-Hll’ velocity. 1|rlr'hat is the magnitude of the tensien in the string between the hem-Ia? lal F 2M {Fag—t” Box l1 H.309 F“? J, ft lief” :. m T MH— (e) Fiery -et'” gal: 2" [cl unknuwn. Hinee the angle til the inclined plane is net- givcn F _ T 5 M a : T This fmhlem is. he cii'lfireat Hum ti" Hm}: were :; 23' i F: on a horiiml-al eat-Face. $ T-: F/z 11. :‘L pendulum he}: of nun-1'3 :Hi' kg; is held :11: an angle ll from the vertical by a horizontal force F: flfl ehewa If t? — 3U“: what is the magnitude- ef F? fl"! :TLfl-‘J'EJ = M3 [a‘j 2.5K H rm In N W? 9—,? T: lei 11a n . l r—em) i.’r' a It 11"”9 ' F [a]. 2.1K 1:: fine The firlin‘l have.) FJ 1;. OPEN“; : “j lflflg tiring”? ‘lfifia harlfinrlul _ mmFaflffl-f Eifi-UfilClDufg-j {an 30-: a? the heartfelt. : We 3. fit. a step light1 a bicycle travelling at iii] In fa DHHSL'ES a car as it starts from rest. The bicycle travels at a cemtant velocity and the car has mnetant mreeieratien 3.0 met. Hear far will the ear have travelled from the atop light at the instant 1when it catches up with the bicycle? (,4: 1‘1 : {LU val-3 t1 : C3 la] 3011] h'kfl bk: bl“: {bill-15m A --—---r 1Rite-nu ; D F art-qr F 3'leffiL [cl 45 ill r r -——1}:ttii «1-4111 —H A, {£3 4 in + U t + L a {L l?) liean of theee “I “r a L“ 2* ear 3 ‘ tam aim git vhf)“ : (wait : Emil“ E 60750 4. Blocks f1 and L5 are connected by [t string and 13111503- 115 511mm. 1153111110 1.11111 1.1111 string 111111 (11111113; 11m 1111153111133, that 1.11111: 11H.- 11:1 f1'11':timml client-5. and that 5:: = LU 111,332. 11' the mass of block B is twice that of block 3'1 (1.0., mg — 21113:}1 'Whilt i5 tlm nutgni’rutlu “1' the 2-1.1:[:1:Je11'u.l.'11111 111' Ihi: blunt-1:1? —-—‘35-l:t‘1:] 3.3 my}? "3' [t1] fiflEELIJ'IE-Iz {CH fi.'|'111'1.."l5'3 fr [nd 1mm of that-c.- ME 5 EMA and: A: F? -:. T- 1‘- WIAO. EtncJ—i Er EI r I'm-.33: WE“ Blink. It" T=m83_mfiq — ME [13-11:] = 1mg (fi'flj E}. Supprme :1 = Hmfl". whun‘: .31 has rliulm'mionfi LfM. H 11:15- 1'11111111114110115 LIL. and (J 1111:: 1'1i111t:n15h'1115 h-‘ILf'l't’ . whart: 31-1 1'1'4'11‘11511n1fi thc- tfilllflflfliflll 11191531 L ICDI‘CECIlti-i the 1'1i1111':111aio11 lungth. Ftfll'l 'I" 111111‘1114011t5 1.111': {11111111151011 M11111. 'l'hcn thn t:>:ptm<:11ts 11?. 111111 :1. 1'1':5]')I:‘.1'!1.11-'(:J;1-' (1.1“... m. [iI'Fs1.., It summit tlfl'v't'r tht': mlunH: L L “M ML n 11] 1. 1 7t “ (*1?) (Ti) -->{bH-.--l L=1im+n émshn (ml—“‘1 M=~1=a+v1 Eavfl'i'1 ‘Znit'flflP‘FH‘r'l ‘1‘” i=1 I= O=-m-—2n=%m=—2v1 av‘WIHF-H) [a] 11011:: mi thase : 1 T?- E .11.: til 'I... L M T : TIFF—ML : E71; 60750 T. The. component-5 of two veeiers: :‘l' and E are as follows: Ax — 2, Ag — —'.i_. A: — {'J' and B; = 2! fly 2 U, B; = 2. When these two vectors are located wit-ll their tails El-t- the same point, what- it: the angle between them? gal—- mini arr Fa- ‘E: : leliel ms 9 e 1A1 = = e; ——1-r'1*“-‘J 6”" 13] $453+ 311+ a; Jeanne-urn" = We? (d) en“ [raj HHIIH ni' il'lEEHII‘ 2 AR E": + is? Jr A151. = {Lil-[2.) +[HLIay +{DX- L) 7- 'J. A. Hi e E» - [Allel use = (is We) {05:19 a 4 _. II. _ '5' i"? wee:% ‘5? 5: me'fie.) — GD 8. SLHJ'Iiug, l'rmll I'H-il.) .‘ti1H-ll' Htiiffflfil'fiifii-‘c WlI.lll‘.tJIIH|P-l.llli }I.i1IIIHlII-!|!'P-l.[.liill lliinf'w' l'ur lllli-i:I Lllen i111- rnerlieieiy begins rimmlurullng will: urinaternl mamlrnnijuil lll mler2 lint-ii il hlflpe. During, i-l'llH moliun. Lire. 11:1.r' Turn-11H in :4. Hri'nigr‘iil.-liilr—e direction. How [311' {loves Line r::1.r' travel? to on r1 ‘1 ‘31 l “at ’r ii 61*? = il‘finlfiblflmdl = seem. {bl FJUU 1n Una: HF. = 1-5;, +- airt : [1D 451M155) -; “)0 Mia 1 'i. (r) Sflflm Pu ——1}'l'illl infill”: UF : G '— ‘Vl‘i‘t. Jr atukl in? it, P— ail — Plifljfil :— 15 3 1- ” me. lo.) lfiilliin {- _; .- .L F {LL + U‘mf J“ iii/C2. = ‘ l:(Welt-Mimi“:(newline; 4»st : lflflflm .9. Elohim A and H are. connected by a string and priileg,r 35 shown. 1931er .95.! with mass 2|] kg: rests wiLhoui. moving on an inclined plane. The inclined plane is inclined at an eagle EI' ; 313‘ from the liorizonnel and the ooefl‘leient of static frienion between the. plane and the block is Ufili. immune the Hiring and {Mlle}.r ere numeleee, the pulley ie frietiorliesel and that g — lfl l'fllH'EE. If the mess of block 13 is larger Then e, oorinin value, bloeli A will Slide 111) the inclined plane. W'hni: ie the value of Wig above which bioel'; fl. will slide up Lhe incline? (a) 3.3 kg k {in} Til kg - [oi 13 lcg —_‘?l:d.l:l .IEI lqj [H3I 2-": leg Jenn; Is)“:- M :flfiflkgwfifl F1 : Trim”- "mfififime : med : 0 33' T {#5. WleflfiflfiEl +Wie‘j 3509 =? mm = meg (fififlflfi-e + an 5:) it? ME = 1913035 meEO‘i- em = H in} -r 60%0 it]. A projectile is elicit into the air With initial speed lflli nifs at an angle 3U” above the horizontal. During; itt; flight: tic”, licfrire it. hits the ground}: what is: the. 'Fflt?!.'t1fl'!£i"hl tipt’lfld of the projectile? wufl" [al 1:: nife 111'!" Min-mm“ Wm 9M5 Mitt/F1 viii-51:33 [it] Her:sz it“? “filial wweflmi’ oi: “4-2,. tc] Fiflmfs 3F“; 35- E"? sin-it. 4‘0 jruwii'a'iiflfla!‘ ti] '.'r‘| rrtlx's Aeneicrq-hm. ——‘}I,r1:] HTmlfa T'Afla nan-tr":- 11+ ill-ac, rmjeciiiflifi Hal‘iiaL at a “if 'u' “a Lidia. = U. C05 5' =(iflfi «(5)1505. ED" '~ 81 We ll. 111 El galax} i'til'. fin“ away. r1 Hintfli’. ship in in unil'tn'rti i:ii'r:l.iiai' unitii'in 2|.r'mnni a large planet. The speed of the space ship ae it 1110W25 in the circular orbit is lililfl 1115’s and 1.!Ii-: i'iLtiiIiH Lil lilE‘. HIJIHEIH eiiip‘e Hi'iiii. ii-: lull X lfl': m. The, iLr::'i-i|el'i-Li.ii:-ri :ii' Lin-i space Hiiip is: {l—L Unimfi EFL} Li'iinifnl'J tiiwnrti li'lE‘. planet. [ll] Lithuafe2 t11fi’:t1.-'ETUII1 the planet {41] (LI Wife? away Fi'nm the. planet. - .— -t ——_-.‘:;.-|:i‘i:| [Ll iiifa'9 tuwnrti Iin: planet. '— 5 «f3: {13] inlltiniwn, Hint-t: we (in not know r; in: the nurfuce of the piui'iet =5 Chi “115"” 'l'a Hamil Hg. [,1 m1 5+ IE. .3. [IHJJJHHI lire-H n. pr'njeutiln as l-Ll‘lriWTl. 'i'l'ln riFiHilrtti line. Hilf‘M-‘H the trajectrjry it would fii‘llmv in the. ahaerree of gravity, and the eelid line shows the actual trajectory {i_e._. with gravity). Puinte T't-‘T, N, 0, and P irerrtefienri te the peeitirirr of the. projectile at three second intewals. Aeenming lg — if] mile}, 1:irheit are the lengths K, Ti?~ and Z? {a} ‘21] mt SD n1,3fi|}in 1'1: Lib-t [Ii] 3&1": in,I i-l'il in_~ 13H in ft] 45 I'll. 135 in. fiat] 111 [ti] 3n m:I EH3 ill) ETD in E ———'} [c] :15 in. lfilfl 111... silt-"i 111 r 1. “t” if“? 1 pq'ent-Vefit’" - EGG-fa") 'fi aids“) : 5451(391 " "iSm rifles}: stir-e (that = item mime 54961;)" = blast. 60750 LL If-i. Ti” |A‘-|- Fil| = Mil + and neither veeter is zerel then: yr. l if E ‘—# “,‘r {a] xii. and In; must be parallel and point in the same direction J, 3.1m: #5, l1] .4. Hillil Hr IIIIIHI in“. parallel and liniiil. in the. HIIIHN-iil.+': flirt-retiun ie 31' and B" must he perpendicular 5E" . 5i: {ti} .«4' and Pi mus-it have: equal magnitudes [e] none 01' these 14:. liiiofltfi .i'i and U are eenneetei‘i h); it etriiig iiiii'l pulley Iii-5 filitlwu. Bliiiik 5i. 11:13 when m, and hleel: B hats inane inf?! tie, lJlflCli We meet: is half that of l'ilL'JCl-i A}. Assume that the string and pulley are iiiaeeleee. that the eurfaee is; l'ri iienieee and liml are he “they frictional ei‘feete. What is the magnitude ef the teneien i the etring'f -. - Blur—k E: [11] Film? flame Medaii'mirf. M fiFB 1T- F35 {(3%) 0‘ eel: a? when pm" é Ti-(EJfi-t e) . I I ‘1- (1. 3 re Fur ea the“: T BI it i. in 5 mt 1F - T -. m I. . A '- [r-i- mine (if these 15. A projectile i5; ghee vertieally upward at 1‘ = [i with an initial speed 1-1]. £th resist-amt: can be ignored. The prejeetiie initially gem; upward: then falls heel: t-e the ground after a Leta! time 111 the air Lair. 011 a eet‘enrl Shot, the ptejeetile has the same initial ruined. but is aimed at an angle 45" aheve the heriaent-al direetieu. llew long 1e‘ill the prejeetile he in the air [before falling!I hae]: m the ground] on the eeeend shot? [all tair First she-l“- u‘ a 1L - aha-Ir Eh] influx-2 ‘I .__-_- C) . .Ir- _ 13¢ lit] Ital-rad _:} {ti-IT F “3‘ [d] til-[NH Ema:an sillw’f: 1,111 : __.__‘;;p {vi-i] Ilium Hr them-i via “— j£1 C} fi SE 4'2. Smut: EIIIIHHHIIH I'm- Exam 1 .' a rl_l_ 1 ...a n_ '*'. . i‘l_'51l53"-|: L— '7'— H.1le 2 [1.5m “mm 3 Mfr-Er: WM” posfifl'” “'5” sin —- _ UREJT; cos-45c = = WW1 W114? = _ 1 ainfifl” _ _ H.865; mama“ — § —- [1.5sz WIHW - S—Efl: — “E — 1'7" mi | By} - 531;; i ré— AH«mHH—-AmRm—-Awgy4—Aznfi 25x E-{AHH: -Akflyfi-+(Azfim—-AmHAfl-L{AmHH—-Awflm]& If]: x — J‘iflsinfl. For vectors; .31. — Axni + :1ij — All"; and E H] — A — For a function of the form fix) 2 aw". where n. is an intngcr, d- . _f_filtlvt:n | and rim __in|]__ 1' ffiflcflx -— n” 13:: I fl. 1f EL particle’s: position is rcprmcnml by 1-: = FIE}. dag?" " (EH ' rib" _ _. cw _ {if __ u‘ 3.11:! a - air '1'11I11I{rfmxcl 191m = j'rxmfljtfi I-L’,T flilfl 3-!{1Hlllflfllblllllfl and ML} — 'rJ:.:I:.|1}rH. — (3', 2mm! Hirrlllarly E'm' 1' - For F1 ncnmmnl. mu:r:lm+1|.]un 31:. w . 1 _. _. _. TU} -— m -|- my! — Eff-IE and NIH.) 'h‘n — m‘. WhE‘J'H Ff] 3.11:] 1'7” :ma Elm lumilfima and vrflnt'ity at. timr). 1'. — |:‘J_~ rtwgwttivcb. flimly falling, uhjtmfi um”: IJLH Earl 1115 HHI'I'H-w. HI11HIH1'P] |.l-l [iEJWIlWJ-Ll'itfi wil h f; — HE 1||_.."'H2. Fm: thiE Exaln. “Ht-‘- I.hE! 2|.ppmxiuu-t.l.itm Ilml g; - m THEE-£2. Unil'm-m circular nmliun: r1 — ‘l'.=?'l."r‘l":. mu] "1"" firm-"Tr. Newt-011’s Second Law: P = mrl'. Star-if: friction: fl; :5. lug; '; 141mm 11‘. fl'iuticm: _.l"i.-. = MN (whim: N iH UH! magnitudu nl' Ihli‘. normal form]. ...
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This note was uploaded on 02/06/2009 for the course PH 317k taught by Professor Richie during the Fall '09 term at University of Texas at Austin.

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exam1_solutions_60730 - KEY PHT .‘t‘l TK Sept-outlier...

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