midterm1-solution - Solution to Problem 1a 20 15 10 5 xl...

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Unformatted text preview: Solution to Problem 1a 20 15 10 5 xl (0) =− 1 xl (1,2) = 0 .5 x u = 1 .25 (2) xu (0,1) =2 0 −5 −10 −15 −20 −4 y −3 −2 −1 x 0 1 2 3 ...
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This note was uploaded on 02/07/2009 for the course COT 3502 taught by Professor Hawkins during the Spring '08 term at University of Florida.

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