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Unformatted text preview: d dx sin-1 ( x ) = 1 cos (sin-1 ( x )) = 1 q 1-x 2 . Thus R sin-1 ( x ) dx = x sin-1 ( x ) + 1 2 1-x 2 + C. It is noted that even though the function sin-1 ( x ) is dened on the closed interval [-1 , 1], its antiderivatives x sin-1 ( x ) + 1 2 1-x 2 + C are only dierentiable on the open interval (-1 , 1). 1...
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- Spring '08
- Integration By Parts