empirical formula - A compound is found to contain 39.12 %...

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A compound is found to contain 39.12 % carbon , 8.772 % hydrogen , and 52.11 oxygen by weight. QUESTION 1: The empirical formula for this compound is Your response: Correct answer:    C 3 H 8 O 3 C_3_H_8_O_3_ . QUESTION 2: The molecular weight for this compound is 92.11 g/mol. The molecular formula for this compound is Your response: Correct answer:    C 3 H 8 O 3 C_3_H_8_O_3_ . Enter the elements in the order presented above Feedback: carbon = C Molar mass = 12.01 g / mol C hydrogen = H Molar mass = 1.010 g / mol H oxygen = O Molar mass = 16.00 g / mol O QUESTION 1: Find the empirical formula for this compound. The EMPIRICAL FORMULA gives the smallest whole number ratio of moles of elements in the compound. Percents by weight: 39.12 % C , 8.772 % H , 52.11 % O In 100 grams of the compound there are:
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39.12 g C 1 mol C = 3.257 mol C 12.01 g C 8.772 g H 1 mol H = 8.685 mol H 1.010 g H 52.11 g O 1 mol O = 3.257 mol O 16.00 g O Divide by the smallest number of moles calculated above to get the lowest mole ratio. 3.257
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This note was uploaded on 02/10/2009 for the course CHEMISTRY 105 taught by Professor Brozak during the Spring '09 term at Washington State University .

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empirical formula - A compound is found to contain 39.12 %...

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