empirical formula

empirical formula - A compound is found to contain 39.12 %...

This preview shows pages 1–3. Sign up to view the full content.

A compound is found to contain 39.12 % carbon , 8.772 % hydrogen , and 52.11 oxygen by weight. QUESTION 1: The empirical formula for this compound is Your response: Correct answer:    C 3 H 8 O 3 C_3_H_8_O_3_ . QUESTION 2: The molecular weight for this compound is 92.11 g/mol. The molecular formula for this compound is Your response: Correct answer:    C 3 H 8 O 3 C_3_H_8_O_3_ . Enter the elements in the order presented above Feedback: carbon = C Molar mass = 12.01 g / mol C hydrogen = H Molar mass = 1.010 g / mol H oxygen = O Molar mass = 16.00 g / mol O QUESTION 1: Find the empirical formula for this compound. The EMPIRICAL FORMULA gives the smallest whole number ratio of moles of elements in the compound. Percents by weight: 39.12 % C , 8.772 % H , 52.11 % O In 100 grams of the compound there are:

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
39.12 g C 1 mol C = 3.257 mol C 12.01 g C 8.772 g H 1 mol H = 8.685 mol H 1.010 g H 52.11 g O 1 mol O = 3.257 mol O 16.00 g O Divide by the smallest number of moles calculated above to get the lowest mole ratio. 3.257
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 02/10/2009 for the course CHEMISTRY 105 taught by Professor Brozak during the Spring '09 term at Washington State University .

Page1 / 5

empirical formula - A compound is found to contain 39.12 %...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online