Homework 6 - Solutions

Homework 6 - Solutions - MAT 33 Fall 2008 Due 1 Homework#6...

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MAT 33 – Fall 2008 Homework #6 - Solutions Due: 10/20/08 1). A cylindrical rod 120mm long and having a diameter of 15mm is to be deformed using a tensile load of 35,000N. It must not experience either plastic deformation or a diameter reduction of more than 1.2 x 10 -2 mm. Of the materials listed below, which are possible candidates? Justify your choice(s). Material Modulus of Elasticity (GPa) Yield Strength (MPa) Poisson’s ratio Aluminium alloy 70 250 0.33 Titanium alloy 105 850 0.36 Steel alloy 205 550 0.27 Magnesium alloy 45 170 0.20 We need to assess the four alloys relative to the two criteria presented. The first criterion is that the material not experience plastic deformation when the tensile load of 35,000 N is applied; this means that the stress corresponding to this load not exceed the yield strength of the material. Upon computing the stress σ = F A o = F π d o 2 2 = 35,000 N π 15 x 10 - 3 m 2 2 = 200 x 10 6 N/m 2 = 200 MPa Of the alloys listed in the table, the Al, Ti and steel alloys have yield strengths greater than 200 MPa. Relative to the second criterion, it is necessary to calculate the change in diameter
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This note was uploaded on 02/10/2009 for the course MAT 33 taught by Professor Keith during the Spring '07 term at Lehigh University .

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Homework 6 - Solutions - MAT 33 Fall 2008 Due 1 Homework#6...

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