GEOG
Lab 1

# Lab 1 - Lab 1 Pressure and the atmosphere Monday 25th of...

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Lab 1: Pressure and the atmosphere Monday, 25th of January 2016 Omolara Afeni TA: Electra Skaarup Lab section: A05 Instructor name: Elyn Humphreys Course number: GEOG2013 PART 1: 1)The volume is constant, therefore, the formula is; P 1 T 1 = P 2 T 2 ,P 2 = P 1 ×T 2 T 1 P1=102kPa, T1=25°C 25+273.15K=298.15K, T2=75°C 75+273.15K=348.15K Where P is pressure and T is temperature. P2= 102 kPa× 348.15 K 298.15 K = 35511.3 kPaK 298.15 K 119.105 kPa 119.105kPa is the pressure of the air in the container if the air inside the container is heated to 75°C Temperature is directly proportional to pressure, so when the temperature of the air within the container increases, the pressure of the air molecules within the container also increase, which will lead to expansion of the container and the container may bust when the pressure gets to a certain point. 2)a) Density decreases exponentially with height because the top of the atmosphere is not exactly defined, so the denser the air near the surface, the more compressible the air is. Pressure also decreases with height because pressure is a result from the weight of overlying atmosphere, so as altitude increases, the weight of the atmosphere decreases, causing the decrease in pressure.

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