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Unformatted text preview: Chapter 22 Radiation Heat Transfer Chapter 22 RADIATION HEAT TRANSFER View Factors 221C The view factor j i F represents the fraction of the radiation leaving surface i that strikes surface j directly. The view factor from a surface to itself is nonzero for concave surfaces. 222C The pair of view factors F i j and F j i are related to each other by the reciprocity rule A F A F i ij j ji = where A i is the area of the surface i and A j is the area of the surface j. Therefore, A F A F F A A F 1 12 2 21 12 2 1 21 = = 223C The summation rule for an enclosure and is expressed as F i j j N = = 1 1 where N is the number of surfaces of the enclosure. It states that the sum of the view factors from surface i of an enclosure to all surfaces of the enclosure, including to itself must be equal to unity. The superposition rule is stated as the view factor from a surface i to a surface j is equal to the sum of the view factors from surface i to the parts of surface j, F F F 1 2 3 1 2 1 3 = + ( , ) . 224C The crossstring method is applicable to geometries which are very long in one direction relative to the other directions. By attaching strings between corners the CrossedStrings Method is expressed as F i i j = Crossed strings Uncrossed strings string on surface 2 221 Chapter 22 Radiation Heat Transfer 225 An enclosure consisting of six surfaces is considered. The number of view factors this geometry involves and the number of these view factors that can be determined by the application of the reciprocity and summation rules are to be determined. Analysis A seven surface enclosure (N=6) involves N 2 2 6 = = 36 view factors and we need to determine 15 2 ) 1 6 ( 6 2 ) 1 ( = = N N view factors directly. The remaining 3615 = 21 of the view factors can be determined by the application of the reciprocity and summation rules. 226 An enclosure consisting of five surfaces is considered. The number of view factors this geometry involves and the number of these view factors that can be determined by the application of the reciprocity and summation rules are to be determined. Analysis A five surface enclosure (N=5) involves N 2 2 5 = = 25 view factors and we need to determine N N ( ) (5 ) = = 1 2 5 1 2 10 view factors directly. The remaining 2510 = 15 of the view factors can be determined by the application of the reciprocity and summation rules. 227 An enclosure consisting of twelve surfaces is considered. The number of view factors this geometry involves and the number of these view factors that can be determined by the application of the reciprocity and summation rules are to be determined. Analysis A twelve surface enclosure (N=12) involves 144 = = 2 2 12 N view factors and we need to determine N N ( ) ( ) = = 1 2 12 12 1 2 66 view factors directly. The remaining 14466 = 78 of the view factors can be determined by the application of the reciprocity and summation rules....
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This homework help was uploaded on 04/18/2008 for the course EML 3007 taught by Professor Chung during the Spring '08 term at University of Florida.
 Spring '08
 Chung
 Heat Transfer

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