anuclear - ANSWERS TO NUCLEAR CHEMISTRY PROBLEM SET 1(a 228Th-> 4He 224Ra(b 110In-> 110Cd(c 110In e-> 110Cd X-ray(d 127I 1H-> 7n 121Xe(e 10B n-> 1H

anuclear - ANSWERS TO NUCLEAR CHEMISTRY PROBLEM SET 1(a...

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ANSWERS TO NUCLEAR CHEMISTRY PROBLEM SET 1. (a) 228 Th ----> 4 He + 224 Ra (b) 110 In ----> β + + 110 Cd (c) 110 In + e - ----> 110 Cd + X-ray (d) 127 I + 1 H -----> 7n + 121 Xe (e) 10 B + n ----> 1 H + 10 Be (f) 10 B + n ----> 4 He + 7 Li (g) 95 Mo + 1 H ----> 95 Tc + n 2. (a) α 4 He (b) 234 U (c) 11 B (d) 90 Sr (e) 15 N (f) 214 Pb (g) β + 3. (a) mass defect = 0.2003 amu (b) 186.5 MeV/atom; 2.988 x 10 -11 J/atom; 1.80 x 10 13 Joule/mole 4. (a) The ratio of n/p for 132 Sn is too high since all stable isotopes have A less than 124. Therefore, β decay (loss of β - particles)mis the only possible mode of decay. 132 Sn ----> 132 Sb + β - (b) Since the atomic mass of U is 238, the 226 U isotope has a n/p ratio which is too low . Since A > 209 and Z >82, the decay mode must be α emission. 226 U ----> 222 Th + α (c) 26

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