N4_presentation

N4_presentation - vx x t t dx Since vx , the value of vx at...

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v x t instant. at that graph t x vs the of slope the of value the us tells t time some at of value the , Since x x v v dt dx = x t
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v v 0 0 0 0 x x t t t t Below are shown two velocity versus time graphs for objects moving along the x axis. Draw the corresponding position versus time graphs below them. For each, assume x (0) = 0.
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v x t dt The area of this rectangle is equal to dx dt v x = The displacement Δ x of the object over some interval of time Δ t is the area under the v x vs t curve, i.e. = = f i t t x x dt t v dt v dx x ) (
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a x t Likewise, we can construct a v x vs t graph from an a x vs t graph, since the two kinematical quantities are related by the equation x x a dt dv = This means that: 1) the value of a x at some instant is equal to the slope of v x vs t at that same instant; 2) = = f i t t x x x x dt t a dt a dv v ) (
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(N4T.2) An object’s x -acceleration a x ( t ) is shown in the boxed graph at the top left of the figure below. Which of the other graphs in the set most correctly describes its x -velocity?
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This note was uploaded on 04/17/2008 for the course PHYS 120 taught by Professor Decarlo during the Spring '08 term at DePauw.

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N4_presentation - vx x t t dx Since vx , the value of vx at...

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