f03x2aan - c) v max = x max , so kg 0.5 kg 2.0 N/m 500 m/s...

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NAME PHYS-1200 PHYSICS II QUIZ 2 OCTOBER 29, 2003 SOLUTIONS PART A. 1. C 4. B 8. E 2. E 5. C 3. C 6. B 7. B PART B . 1. a) TO THE LEFT The same direction as the current in the wires. b) INTO THE PAGE Based on the direction of the current and the right hand rule. 2. a) s t x v 06 . 0 m 0 . 3 = = v = 50 m/s b) The wavelength can be read directly from the graph. λ = 4.0 m 3. a) EQUAL TO 500 Hz Since the cars are moving at the same speed in the same direction, there is no Doppler shift. b) YES, BECAUSE THE REFLECTED WAVE HAS A HIGHER FREQUENCY THAN THE ONE THAT COMES DIRECTLY FROM THE CAR.
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NAME PART C . 1. a) kg 5 . 0 kg 0 . 2 N/m 500 2 1 2 1 + = + = π m M k f f = 2.25 Hz b) The maximum potential energy equals the maximum kinetic energy. Immediately after the bullet hits, the system has maximum kinetic energy. U max = K max = ½(M + m)V² = ½ (2.0 kg + 0.5 kg)(3.0 m/s)² U max = 11.3 J
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Unformatted text preview: c) v max = x max , so kg 0.5 kg 2.0 N/m 500 m/s . 3 max max max + = + = = m M k v v x x max = 0.21 m = 21 cm Or, using energy, K max = U max = k x max , so m 21 . N/m 500 J) 3 . 11 ( 2 2 max max = = = k U x d) From conservation of momentum, mv = ( M + m ) V , so m/s) 5(3.0 m/s) . 3 ( kg 0.5 kg 5 . kg . 2 = + = + = V m m M v v = 15 m/s 2. a) NEGATIVE x DIRECTION It moves in the direction of E B . b) Hz 10 1.5 m/s 10 . 3 6 8 = = f c = 2.0 10 2 m = 200 m c) The maximum magnetic flux must pass through the loop to induce the maximum current. d) LC f 1 2 1 = , so LC f 1 4 1 2 2 = , and H) 10 4 . 1 ( Hz) 10 5 . 1 ( 4 1 4 1 4 2 6 2 2 2- = = L f C C = 8.0 10-11 F = 80 pF...
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This test prep was uploaded on 04/18/2008 for the course PHYS 1200 taught by Professor Stoler during the Spring '06 term at Rensselaer Polytechnic Institute.

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f03x2aan - c) v max = x max , so kg 0.5 kg 2.0 N/m 500 m/s...

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