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Unformatted text preview: x = 0. Therefore, the displacements on the positive side of x = 0 must move toward x = 0. The wave moves in the negative x direction. NAME PART C . 1. a) N Φ B = Li , so 5 A) H)(1.5 10 . 4 ( 6× = = Φ N Li B Φ B = 1.2 ×106 Wb b) 2 6 2 1 2 2 1 A) H)(1.5 10 . 4 (× = = Li U B U B = 4.5 ×106 J = 4.5 μ J c) The magnitude is given by, A/s) H)(6.0 10 . 4 ( 6× = = dt di L E . E = 2.4 ×105 V = 24 V d) FROM RIGHT TO LEFT. It opposes the increase of current. 2. a) k m T π 2 = , so k m T 2 2 4 = , and 2 2 2 2 4 N/m) 80 ( s) 0010 . ( 4 = = k T m m = 2.0 ×106 kg = 2.0 ×103 g = 2.0 mg b) 2 2 1 m kx E = , so k E x m 2 2 = , and N/m 80 ) J 10 . 4 ( 2 2 9× = = k E x m x m = 1.0 ×105 m = 10 m c) LC T 2 = , so LC T 2 2 4 = , and F) 10 . 1 ( 4 s) 0010 . ( 4 6 2 2 2 2× = = C T L L = 2.5 ×102 H = 25 mH d) C Q U 2 2 = , so CU Q 2 2 = , and ) J 10 . 4 )( F 10 . 1 ( 2 2 9 6× × = = CU Q Q = 8.9 ×108 C...
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This test prep was uploaded on 04/18/2008 for the course PHYS 1200 taught by Professor Stoler during the Spring '06 term at Rensselaer Polytechnic Institute.
 Spring '06
 Stoler
 Physics, Current

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