{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

# pre2anss06 - LC f LC f ϖ b One quarter of a period is...

This preview shows pages 1–2. Sign up to view the full content.

PHYS-1200 PHYSICS II SPRING 2006 PREVIEW QUIZ 2 - ANSWERS PART A. 1. B 7. D 2. B 8. E 3. C 4. E 5. D 6. A PART B. 1. a) λ = 2 π / k = 2 π /(0.5 π m -1 ) = 4.0 m y m = 4.0 cm b) T = 2 π / ϖ = 2 π /(20 π s -1 ) = 0.10 s y m = 4.0 cm

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
2. INTO THE PAGE PART C. 1. a) . Then, , and N/m [ Hz)] f k m f k m m k f = = = = 1 2 1 2 2 6400 2 400 2 2 2 2 π π π π ( ) ( ) ( m = 1.0 × 10 -3 kg = 1.0 g ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ b) λ = v / f = (343 m/s)/(400 Hz) λ = 0.86 m = 86 cm ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ c) m/s) 40 m/s (343 m/s 343 Hz) 400 ( ' - = + = S v v v f f f’ = 453 Hz pF 0 . 1 F 10 1.0 = ) 10 0 . 1 ( )] 10 0 . 5 ( 2 [ 1 ) 2 ( 1 1 ) 2 ( and 1 2 so 1 and 2 a) 2. 12 - 3 2 6 2 2 = × ×
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: LC f LC f ϖ b) One quarter of a period is required for the current to go from zero to its maximum value. 4 s 10 . 2 4 so s 10 . 2 Hz 10 . 5 1 1 7 7 6--× = = ∆ × = × = = T t f T ∆ t = 5.0 × 10-8 s = 50 ns ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ c) = c / f = (3.0 × 10 8 m/s)/(5.0 × 10 6 Hz) = 60 m ¯¯¯¯¯¯¯¯...
View Full Document

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern