quiz2.m - end C =(t 10(1-exp-0.04*t 4*exp-0.04*t actualC =...

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% Minwook Kim % quiz2 f = @(t) 10*(1-exp(-0.04*t)) + 4*exp(-0.04*t) - 0.93*10; df = @(t) 0.04*10*exp(-0.04*t) - 0.04*4*exp(-0.04*t); iter = 1; xold = 3; xnew = xold - f(xold)/df(xold) while (abs(xnew-xold) > eps) iter = iter + 1; xold = xnew; xnew = xold - f(xold)/df(xold);
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Unformatted text preview: end C = @(t) 10*(1-exp(-0.04*t)) + 4*exp(-0.04*t); actualC = C(xnew); disp(['Time required for C to be 93% of Cin = ',num2str(xnew), ' seconds']); disp(['Actual C = ' ,num2str(actualC)]) disp(['Number of iterations = ', num2str(iter)])...
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