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**Unformatted text preview: **)-sin( πt )] . (1) We know as a Fourier transform pair that cos(2 πf t ) ↔ 1 2 [ δ ( f-f ) + δ ( f + f )] and sin(2 πf t ) ↔ 1 2 j [ δ ( f-f )-δ ( f + f )] . We also know as a Fourier transform pair that A ↔ Aδ ( f ) . Thus, the Fourier transform of s ( t ) in (1) can be obtained as S ( f ) = 1 2 δ ( f )-1 4 [ δ ( f-2) + δ ( f + 2)] + 1 4 j ± δ ² f-3 2 ³-δ ² f + 3 2 ³´-1 4 j ± δ ² f-1 2 ³-δ ² f + 1 2 ³´ . 2...

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- Spring '16
- TUtorial And Note, fourier transform pair