SG 10 key - t Practice problems for CHEM 1007 study groups...

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Unformatted text preview: t Practice problems for CHEM 1007 study groups “,ka (0 [you “I ll: > 1. For diatomic molecules where both atoms have 2 s 7 the op bonding MO is at: a higher energy than the rap bonding M0 [see figure 9.13 p 278 of textbook]. For diatomic molecules where both atoms have 2 > 7 the op bonding M0 is at a lower energy than the :tp bonding MO. [a] Use this information to draw molecular orbital diagrams for B2 and F24 (b) Determine the bond order for each molecule (B: and F2} _ 6; [c] Determine if each molecule [82 and F2] are paramagnetic or diamagnetic. (a) __ r; — [ill ’55. 75?; :TRPA Tr-TPr ‘ 62 B). :5 Fa l'ziwmjru‘h C -—- ._l: 4i» _. 1 9' "l *— :'J. 5’ ‘Q ‘- . - fl APE ? 73?; ___{_’. 73:1,, 60}. AC ) I F)— :5 A?“ .fi’l/lajllu‘v'ht it my 031’2 e3; .12.; co: 013-: 0'25 5-5"— 2. Chemists in the laboratory have determined that 32 is a paramagnetic compound. Explain how this observation confirms that the up molecular orbitals are at a lower energy than the Up molecular orbitals for 32. I16 TIP kiwi/ban 5} k JP ('7' [D we,“ Hum “l0 l a; a, I; a; w 1M5 fl (7W1 . ' ffl‘i'c Fit 144101790 6; w“ was IS fldml’ 3 $7 21": 17:; oi— ix. “3‘ awn. __._¥ flip? ___$ 33+? T9 ms M “W ’9...- ,0! [jg—“9 Tr” ’ 297 I T— W t 1 — F‘- ‘ ' .. 5—— .jr-g é“ M3, 13-; “'7 We 5P 5,1 were 029,3. {1 K53 in pummea'lwf‘i' flit-+5 '5" < m; is 0115' 3-. Draw the molecular orbital diagram for CF. Would you expect the bond length of CFt to be longer or shorter than CF? [Assume that CF and Cl“ have the Z > 7 MO scheme). C * F "‘ F CF: (cai‘fofi/ozdeml‘[rial . (30: 3'; (9—3): 25 _ F lug) Miller It ._. _ :- .5 item mime Bu— 1/; (9 2) do __ 1 '3 will Mimi’E CF+ M5 CZ gnu-tit!” BO 5‘, ”L f “7‘ Exile”) wfll wat (1.. snub-'1" kW): ’1”? h I “01 L ' ...
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