This preview shows pages 1–4. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentThis preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: 33.1: a) . s m 10 04 . 2 47 . 1 s m 10 00 . 3 8 8 = = = n c v b) . m 10 42 . 4 47 . 1 ) m 10 50 . 6 ( 7 7 = = = n 33.2: a) . m 10 17 . 5 Hz 10 5.80 s m 10 00 . 3 7 14 8 vacuum = = = f c b) . m 10 40 . 3 Hz)(1.52) 10 80 . 5 ( s m 10 00 . 3 7 14 8 glass = = = fn c 33.3: a) . 54 . 1 m/s 10 1.94 m/s 10 00 . 3 8 8 = = = v c n b) . m 10 47 . 5 ) m 10 55 . 3 ( ) 54 . 1 ( 7 7 = = = n 33.4: 1.501 m)(1.333) 10 38 . 4 ( 7 Benzene water water Benzene Benzene water water 2 = = = n n n n CS . 5 . 47 equal always are angles reflected and Incident a) = = a r : 33.5 b) . . 66 5 . 42 sin 66 . 1 00 . 1 arcsin 2 sin arcsin 2 2 =  =  = = a b a b b n n 33.6: s m 10 17 . 2 s 10 5 . 11 m 50 . 2 8 9 = = = t d v 38 . 1 m/s 10 2.17 m/s 10 00 . 3 8 8 = = = v c n 33.7: b b a a n n sin sin = s m 10 51 . 2 194 . 1 / ) m/s 10 00 . 3 ( so 194 . 1 1 . 48 sin 7 . 62 sin 00 . 1 sin sin 8 8 = = = = = = = n c v v c n n n b a a b 33.8 (a) Apply Snells law at both interfaces. 33.9: a) Let the light initially be in the material with refractive index n a and let the third and final slab have refractive index n b Let the middle slab have refractive index n 1 1 1 sin sin : interface 1st n n a a = b b n n sin sin : interface 2nd 1 1 = . sin sin gives equations two the Combining b b a a n n = b) For N slabs, where the first slab has refractive index n a and the final slab has . sin sin , , sin sin , sin sin , index refractive 2 2 2 2 1 1 1 1 b b N N a a b n n n n n n n = = = of angle on the depends travel of direction final The . sin sin gives This b b a a n n = incidence in the first slab and the indicies of the first and last slabs. 33.10: a) . 5 . 25 . 35 sin 33 . 1 00 . 1 arcsin sin arcsin air water air water = = = n n b) This calculation has no dependence on the glass because we can omit that step in the . sin sin sin : chain water wate glass glass air air r n n n = = 33.11: As shown below, the angle between the beams and the prism is A/2 and the angle between the beams and the vertical is A, so the total angle between the two beams is 2A. 33.12: Rotating a mirror by an angle while keeping the incoming beam constant leads rotation. mirror the from arose 2 of deflection additional an where 2 2 becomes beams outgoing and incoming between angle the Therefore . by angle incident in the increase an to + 33.13: . 71.8 62.0 sin 1.58 1.70 arcsin sin arcsin = = = a b a b n n 33.14: 38.2. 45.0 sin 1.52 1.33 arcsin sin arcsin = = = a b a b n n...
View
Full
Document
This homework help was uploaded on 02/26/2008 for the course PHYS 11 and 21 taught by Professor Hickman during the Spring '08 term at Lehigh University .
 Spring '08
 Hickman

Click to edit the document details