Alg2HonModelCurr_201415

Alg2HonModelCurr_201415 - Mathematics Curriculum Algebra...

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Mathematics Curriculum: Algebra 2/2 Honors 1
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Algebra 2 Mapping: Algebra 2 Unit Plan/Development: Mathematics: Algebra 2 Unit #1: Polynomials 9/4/14-10/24/14 Unit #1 Standard Description Student Learning Objectives Performance Tasks/Critical Thinking N.CN.7 A.REI.4.b Solve quadratic equations with real coefficients that have complex solutions. Solve quadratic equations in one variable. b. Solve quadratic equations by inspection (e.g., for x2 = 49), taking square roots, completing the square, the quadratic formula and factoring, as appropriate to the initial form of the equation. Recognize when the quadratic formula gives complex solutions and write them as a ± bi for real numbers a and b. Solve quadratic equations with real coefficients that have complex solutions. Writing Task 1. If you are asked to write a polynomial function of least degree with zeros of 2 and sqrt 7, what would be the degree of the polynomial? Explain. 2. You are designing a cylindrical, plastic glass with an outside layer of water that, when frozen, keeps the contents of the glass cold. The outer height of the glass should be four times its outer radius, and the thickness of the sides and bottom of the glass should be 1 cm. The glass is to hold 140pi cubic centimeters of 2 Date s September 4- October 24, 2014 October 27 – December 22 2014 January 5 –Feb 27 2015 March 2 – Apr 24, 2014 Apr 27-June 19, 2014 5 Weeks Instructio n 2 Weeks Assessment/ Enrichment/ 5 Weeks Instructio n 2 Weeks Assessment/ Enrichment/ 5 Weeks Instructio n 2 Weeks Assessment/ Enrichment/ 5 Weeks Instructio n 2 Weeks Assessment/ Enrichment/ 5 Weeks Instructio n 2 Weeks Assessment/ Enrichment/ Math Unit 1 Asmnt 1/Unit 1 Unit 2 Asmnt 2/Unit2 Unit 3 Asmnt 3/Unit 3 Unit 4 Asmnt 4/Unit 4 Unit 3 Asmnt 5/Unit 5
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liquid: Critical Thinking a. Why might you have chosen 140pi cubic cm for the capcity of the glass? (1floz=29.537 cubic cm) A.APR.2 Know and apply the Remainder Theorem: For a polynomial p(x) and a number a, the remainder on division by x – a is p(a), so p(a) = 0 if and only if (x – a) is a factor of p(x). Restructure by performing arithmetic operations on polynomial/rational expressions. b. Write a function V 1 (x) for the volume of liquid the glass can hold. Substitute 140 pi for V 1 (x) and rewrite the resulting equation in standard form. A.SSE.2 A.APR.3A Use the structure of an expression to identify ways to rewrite it. For example, see x4 – y4 as (x2)2 – (y2)2, thus recognizing it as a difference of squares that can be factored as (x2 – y2)(x2 + y2). Identify zeros of polynomials when suitable factorizations are available, and use the zeros to construct a rough graph of the function defined by the polynomial. Use an appropriate factoring technique to factor expressions completely including expressions with complex numbers.
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