hw7_2.pol - rc = r1 r2 2*r3 rd = r1 2*r2 r3 re = r2 rf = r3...

Info icon This preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
No Title |POLVER05_0 |1 d(Ff) / d(V) = rf Ff(0) = 0 d(Fe) / d(V) = re Fe(0) = 0 d(Fd) / d(V) = rd Fd(0) = 0 d(Fc) / d(V) = rc Fc(0) = 0 d(Fb) / d(V) = rb Fb(0) = 20 d(Fa) / d(V) = ra Fa(0) = 15 V(0) = 0 V(f) = 100000 Ft = Fa + Fb + Fc + Fd + Fe + Ff ra = -r1 - 3*r2 rb = -2*r1 - r3
Image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: rc = r1 + r2 - 2*r3 rd = r1 - 2*r2 + r3 re = r2 rf = r3 r1 = k1*Ca*Cb^2 r2 = k2*Ca*Cd r3 = k3*Cb*Cc^2 k1= 0.25 k2= 0.1 k3= 5.00 Ca = Fa/Ft * Ct0 Cb = Fb/Ft * Ct0 Cc = Fc/Ft * Ct0 Cd = Fd/Ft * Ct0 Ce = Fe/Ft * Ct0 Cf = Ff/Ft * Ct0 Ct0 = 3.5...
View Full Document

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern