hw7_2c.pol

# hw7_2c.pol - No Title |POLVER05_1 |2 f(Ca = Ca0 Ca ra*tau...

• Homework Help
• 1
• 100% (3) 3 out of 3 people found this document helpful

This preview shows page 1. Sign up to view the full content.

No Title |POLVER05_1 |2 f(Ca) = Ca0 - Ca + ra*tau f(Cb) = Cb0 - Cb + rb*tau f(Cc) = Cc0 - Cc + rc*tau f(Cd) = Cd0 - Cd + rd*tau f(Ce) = Ce0 - Ce + re*tau f(Cf) = Cf0 - Cf + rf*tau Ca0 = 1.5 Cb0 = 2 Cc0 = 0 Cd0 = 0 Ce0 = 0 Cf0 = 0 tau = 5 Ca(0) = .5 Cb(0) = .5 Cc(0) = .5 Cd(0) = .5
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Ce(0) = .5 Cf(0) = .5 ra = -r1 - 3*r2 rb = -2*r1 - r3 rc = r1 + r2 - 2*r3 rd = r1 - 2*r2 + r3 re = r2 rf = r3 r1 = k1*Ca*Cb^2 r2 = k2*Ca*Cd r3 = k3*Cb*Cc^2 k1= 0.25 k2= 0.1 k3= 5.00 Sp = Cd/(Cc+Cd+Ce+Cf) Xa=(Ca0-Ca)/Ca0 Xb = (Cb0-Cb)/(Cb0)...
View Full Document

• Spring '14
• LanceL.Lobban

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern