Chem142_KineticsI_Report_111215

Chem142_KineticsI_Report_111215 - Page 1 of 36 Name Rebeca...

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Page 1 of 36 Name: Rebeca Bosques Quiz Section: 142 cc ID Number: 1531414 Lab Partner: Firas atiya Grading: 60 pts. (Lab notebook pages are worth 10 pts - total for report and notebook is 60 Stock Solutions Soln. Conc. Units 0.0005 M 0.010 M 0.040 M HCl 0.100 M Table of Recorded Reagent Volumes, Temperature, Time of Reaction, and Calculated Rate Experiment Test Tube #1 Test Tube #2 Temp. D Run Celsius Time # mL mL mL mL mL C sec. 1 0.00 0.50 1.00 0.50 0.50 23.33 43.8 2 0.25 0.50 0.75 0.50 0.50 23.25 82.8 3** 0.50 0.50 0.50 0.50 0.50 22.35 131 4 0.75 0.50 0.25 0.50 0.50 22.13 203 5 0.00 0.50 0.50 1.00 0.50 23.63 54.8 6 0.25 0.50 0.50 0.75 0.50 23.38 81.5 7** 0.50 0.50 0.50 0.50 0.50 23.53 136.5 8 0.75 0.50 0.50 0.25 0.50 23.58 223 9 0.00 0.50 0.50 0.50 1.00 23.65 22.5 10 0.25 0.50 0.50 0.50 0.75 23.9 47.8 11** 0.50 0.50 0.50 0.50 0.50 23.5 107.8 12 0.75 0.50 0.50 0.50 0.25 23.13 491.8 13 0.50 0.50 0.50 0.50 0.50 280.1 14* 0.75 0.50 0.50 0.50 0.25 22.26 56.8 15* 0.75 0.50 0.50 0.50 0.25 85.3 * Measurements made with a drop of 1.0 mM Ammonium Molybdate ** Repeated measurements for calculating k and Ea A drop of 1% Starch indicator solution is included in each run. S 2 O 3 2- I - BrO 3 - H 2 O S 2 O 3 2- I - BrO 3 - H + Chem 142 Experiment #5 Kinetics I: Method of Initial Rates Data, Calculations and Graphs By signing below, you certify that you have not falsified data, that you have not plagiarized any part of report, and that all calculations and responses other than the reporting of raw data are your own indep work. Failure to sign this declaration will result in 5 points being deducted from your report score. Signature: Show your calculation for the "Rate" here using data for Run #1 : Note: All sections report must be typ
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Page 2 of 36 Table of Recorded Temperature, Initial Concentrations, Time of Reaction, and Calculated Ra Experiment Temp Initial Concentrations (M) Time Rate Run # Celsius sec M/sec Run 1 23.33 1x10^-4 0.0040 0.0200 0.0080 43.8 2.28 x 10^-5 Run 2 23.25 1x10^-4 0.0030 0.0200 0.0080 82.8 1.41x10-5 Run 3 22.35 1x10^-4 0.0020 0.0200 0.0080 131 1.02x10^-5 Run 4 22.13 1x10^-4 0.0010 0.0200 0.0080 203 7.39x10^-6 X-axis Y-axis log(Rate) -2.4 -4.642 -2.5 -4.851 -2.7 -4.991 -3.0 -5.131 S 2 O 3 2- I - H + BrO 3 - log(I - ) Reaction Order Determination for I - Show your calculation for the concentration of BrO 3 - used in Runs 1-4 : (5x10^-4L)(0.040M)= 2x10^-5 mol BrO 3 - 2x10^-5 mol BrO 3 - /0.0025L= 0.008 M READ THIS BEFORE PROCEEDING: Recall that since BrO 3 - and H + are held constant, the rate law takes on the following form: Rate = B[I - ] i where "B" is the pseudo rate constant that includes k, [H + ], and [BrO 3 - ]. Therefore, a plot of log(Rate) vs. log([I - ]) (y-axis vs x-axis) will yield a straight line with a slope equal to i, the order of the reaction with respect to I - . Place your plot relating to the reaction order for I - here, making it large enough to cover this box (so that it is easy to read).
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