Biology Lecture#5 - Biology Lecture#5 The way to predict an...

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Biology Lecture #5 The way to predict an outcome of a monohybrid cross can be done with a Punnett square o For one gene with 2 alleles, there are 1x2 = 2 possible genotypes (gametes) o Combining 2 different gametes from each of two parents 2x2 = 4 possible genotypes (gametes) crossing over does not influence the frequency of gametes for independently assorting genes o the a and b alleles remain on their original chromosomes o crossing over will affect the b locus the general rule o for n different genes assorting independently there are 2x2x2….= 2^n possible haploid genotypes (gametes) so for 23 different genes all on a different human chromosome, 2^23 = 8, 388, 608 different haploid gamete genotypes the further apart two genes are on a chromosome, the more likely they will assort independently of the 21 possible dihybrid crosses that Mendel could have done, only one would have
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Unformatted text preview: involved two genes that don’t segregate independently the forked line method for predic´ng the outcome of a cross involving three independly assor´ng genes the rules of probability – the mul´plica´ve rule o if events A and B are independent, the probability that they occur together ifs the product of their individual probabili´es of occurrence P(A) x P(B) The rules of probability – the addi´ve rule o If the events A and B are independent, then the probability that at least one of them occurs is the sum of their individual probabili´es of occurrence minus the probability of their joint occurrence P(A) + P(B) – (P(A) x P(B)) o If the events A and B are independent and don’t occur together, the probability that at least one of them occurs is the sum of their individual probabili´es of occurrence P(AP + P(B)...
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  • Summer '14
  • Genetics, individual probabilities, haploid gamete genotypes

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