Newtons second law - template (1)

Newtons second law - template (1) - Lab report Newtons...

Info icon This preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
Lab report- Newton’s second law of motion Objective: the objective of this lab is to validate Newton’s second law of motion Data: Mass of the cart = 504.1, grams Mass of the hook = 5.4, grams Experiment # 1 Mtot= VALUE +- UNCERTAINTY , UNITS Run Mass of the hanger Acceleration of the system g m/s 2 1 5.4 0.00468+/-0.0034 2 5.4+10 0.179+/-0.0031 3 5.4+30 0.531+/-0.011 4 5.4+40 0.680+/-0.012 5 5.4+45 0.774+/-0.013 slope = VALUE +- UNCERTAINTY , UNITS net force (weight of cart +hanger), N Acceleration (m/s 2 ) 5.095 0.00468+/-0.0034 5.195 0.179+/-0.0031 5.395 0.531+/-0.011 5.495 0.68+/-0.012 5.545 0.774+/-0.013 Graph of acceleration against net force
Image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
5 5.1 5.2 5.3 5.4 5.5 5.6 0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 f(x) = 1.7x - 8.66 net force (N) acceleration (m/s2) experiment # 2 g = value -+ uncertainty, units Run Mass on the hanger Acceleration 1(system moves towards motion sensor) Acceleration 2 (system moves away from motion sensor) A ave g Grams m/s2 m/s2 m/s2 m/s2 1 5.4+45 0.919+/-0.012 0.847+/-0.01 0.883 9.715 2 5.4+40 0.819+/-0.015 0.704+/-0.027 0.7615 9.217 3 5.4+30 0.739+/-0.015 0.599+/-0.019 0.669 10.20 4 5.4+10 0.322+/-0.013 0.265+/-0.0069 0.2935 9.901 5 5.4+5 0.205+/-0.002 0.170+/-0.0018 0.1875 9.276 6 5.4 0.127+/-0.004 0.0722+/-0.0012 0.0996 9.397 Data analysis: 1. From the formula of the second law; F=ma For a graph of acceleration against net force, the slope= acceleration/ net force
Image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern