A person throws ball at angle - o DX=Vi(t 1/2a(t)^2 set to...

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12. A person who is 1.3 m tall throws a ball with a speed of 11 m/s at an angle of 67 degrees above the horizontal, as shown in the diagram below. h = 1.3 m , v = 11 m/s , θ = 67 degrees Use the acceleration due to gravity as g = 10 m/s 2 . What are the x and y components of the initial velocity? o ( 4.298042 , 1.012555×10 1 ) m/s What are the x and y components of the ball's velocity when it is at its maximum height? o ( 4.298042 , 0.000000 ) m/s What are the x and y components of the ball's velocity the instant before it hits the ground?---- USE THE M/S FOUND IN THE FIRST PART TO FIND Y: V^2=Vi^2+2aDX o ( 4.298042 , -1.133697×10 1 ) m/s What is the ball's speed (the magnitude of the velocity) the instant before it hits the ground? o ((4.3^2)+(11.34^2))^1/2 o 1.212436×10 1 m/s What is the time of flight; that is, the time taken for the ball to hit the ground after it has left the person's hand?
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Unformatted text preview: o DX=Vi(t)+1/2a(t)^2- set to zero and do quadratic eqn o 2.146252 s *******CHECK THIS 13. To push a 8-kg crate up a frictionless incline angled at 10° to the horizontal, a worker exerts a force of 190 N parallel to the incline. The crate moves a distance of 7 m. Fc = 80N @ 10deg. Fp = 80sin10 = 13.9 N.=Force parallel to incline. Fv = 80cos10 = 78.8N. = Force perpendicular to incline = Normal. o What work is done on the crate by the worker? W = Fd = 190 * 7 = 1330J o What work is done on the crate by gravity? Wc = mg=weight of crate=80 W = Fc*d=Fc*h=-80 * 7sin10 W=-97.2 o What is the work done on the crate due to the normal force of the inclined plane surface? o What is the net work done on the crate? 1232.8 (1330+(-97.2))...
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