Statss2 - d 208.5 Norm.Inv at 1 confdence level 6 7.1 a...

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Julio C Lopez MAST 6201 4/2/2016 Homework Session #2 1.) 6.1 From Standard Normal Table a. 0.9418 b. 0.0329 c. 0.0253 d. 0.9747 2.) 6.5 0.9938 1-Norm.Dist(75,100,10,True) 0.00135 Norm.Dist(70,100,10,True) 0.0228 Pr(X>110) 0.1587 0.1815 Sum(Norm.Dist(80,100,10,True),1-(Norm.Dist(110,100,10,True)) 87.2 Norm.Inv at 10% confidence level 112.8 Norm. Inv at 90% confidence level 3.) 6.7 4.) 6.9 a. 0.2119 1-Norm.Dist(25,21,5,True) b. 0.4068 Norm.Dist(20,21,5,True)-Norm.Dist(10,21,5,True) c. 30.80 Norm.Inv at 97.5% confidence level 11.2 Norm.Inv at 2.5% confidence level a. Pr(X>75) b. Pr(X<70) c. Pr(X<80) d. 80% btwn which 2 X
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Julio C Lopez MAST 6201 4/2/2016 Homework Session #2 5.) 6.11
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Unformatted text preview: d. 208.5 Norm.Inv at 1% confdence level 6.) 7.1 a. 0.0015 Z(95): -2.96 b. 0.0679 Z(97.5):-1.48 c. 0.0968 Z(102.2): 1.30 d. 99.348 Z value: -0.39 7.) 7.5 a. The sampling distribu±on of themean is the distribu±on of all possible means if we select all possible sample of a given size. b. 0.0228 Z(2.61): -2.00 c. 0.6826 Z(2.64): 1.00 , Z(2.62): -1.00 d. 2.638 and 2.6216 Z(80%): 0.84 , Z(20%): -0.84 8.) 7.7 a. 0.3830 Z(7.8): -0.50 , Z(8.2): 0.50 Julio C Lopez MAST 6201 4/2/2016 b. 0.3944 Z(7.5): -1.25 , Z(8): 0.00 c. 0.6826 Z(80%): 0.84 , Z(20%): -0.84 d. We can see that the Pr of the sample mean being between 7.8 and 8.2 is higher with 100 sessions than with 25 sessions because with the increasing number of sessions the sample mean distribuTon narrows around the mean. ±hus, the probability is larger for more sessions....
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