# Stats3 - Julio C Lopez MAST 6201 Homework Session#3 1 8.15...

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Julio C Lopez MAST 6201 4/9/2016 Homework Session #3 1.) 8.15 s = 0.00 n = 100 confidence = 95% a. Lower bound = 2.463 2.55-T.Inv.2t(0.05,99)*0.44/sqrt(100) Upper bound = 2.637 2.55+T.Inv.2t(0.05,99)*0.44/sqrt(100) 2.) 8.17 x-bar = 195.3 n = 18 confidence = 95% a. Lower bound = 184.66 195.3-T.Inv.2t(0.05,17)*21.4/sqrt(18) Upper bound = 205.94 195.3+T.Inv.2t(0.05,17)*21.4/sqrt(18) x-bar = 0.00 b. Assuming the mean value is contained in our confidence interval, we could use it to fine the range of balues for the total worth on her inventory. s = 21.4 b. We should not accuse the manufacturer of failing to meet the performance information claimed because the claimed value of 200 is within the confidence interval. c. It's not unusual because the confidence interval is only describing the estimate population mean value. There can still be individual values outside of it. 210 is within the StDev of the sample mean so it's not unlikely.

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Julio C Lopez MAST 6201 4/9/2016 Homework Session #3 3.) 8.19 (a & b only) x-bar = 25.75 n = 16 confidence = 95% a. Lower bound = 22.48 25.75-T.Inv.2t(0.05,15)*6.137/sqrt(16) Upper bound = 29.02 25.75+T.Inv.2t(0.05,15)*6.137/sqrt(16) b. One can be 95% confident that the population mean of MPG of family sedan will lie between 20.94 and 30.60
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