Unformatted text preview: deviation is known to be = 0.3 cm. A sample of 50 bolts has a mean length of = 14.85 cm. In this case = 0.3, n = 50, = 14.85. The approach is to find a confidence interval of 95% is given by: 14.85 ± 1.96 × i.e. (14.77, 14.93) cm Interpretation  with 95% confidence the interval (14.77, 14.93) contains the population mean µ of all bolts produced by the process. The interval does not contain 15.0cm. The manager at that time may determine that the production machinery be recalibrated to get the bolt lengths closer to 15 cm. N/A. (2015). TScore vs. ZScore: What’s the Difference? Statistics How To. Retrieved 1/19/2016. ...
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 Spring '13
 WenjunGu
 Statistics, Normal Distribution, Standard Deviation, individual scores

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