KAI LING CHEM111_Lab08-Vapor_Report_form_wk1 (1)

KAI LING CHEM111_Lab08-Vapor_Report_form_wk1 (1) - Linear...

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Liquid-Vapor Equilibrium - Report Form EACH STUDENT WILL SUBMIT THEIR OWN LAB REPORT, GRAPHS, AND CALCULATIONS. ALL OF THESE MUST BE COMPLETED BY THE INDIVIDUAL STUDENT. Name: Kai Ling Partner(s): Mohemed Elsonbly Results: Ethanol Sample Room Temperature (˚C): 21.5 Barometric Pressure (mm Hg): 756.9 Table of temperature and pressure of ethanol Temp ( o C) Measured pressure (inches Hg) Temp (K) Vapor pressure (atm) 1/T (K -1 ) ln(P) 21 27.6 294 0.0735 3.40×10 -3 -2.610 26 27.5 299 0.0768 3.34×10 -3 -2.566 31 26.7 304 0.104 3.29×10 -3 -2.267 36 25.3 309 0.154 3.24×10 -3 -1.868 41 23.8 314 0.201 3.19×10 -3 -1.607 46 21.9 319 0.264 3.14×10 -3 -1.332 49 20.6 322 0.307 3.11×10 -3 -1.179 51 19.2 324 0.354 3.09×10 -3 -1.048 54 17.9 327 0.398 3.06×10 -3 -0.922 56 16.3 329 0.451 3.04×10 -3 -0.796 59 13.1 332 0.562 3.01×10 -3 -0.576 61 12.7 334 0.576 2.99×10 -3 -0.552 65 9.8 338 0.672 2.96×10 -3 -0.396 Insert the cooling measurements in the appropriate temperature positions so that the temperature/vapor pressures are continually increasing.
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Plot of pressure (atm) vs. temperature (K) for ethanol (copy CTRL+c and paste CTRL+v) Plot of ln(P) vs. 1/T (K -1 ) for ethanol with linear fit (copy CTRL+c and paste CTRL+v)
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Unformatted text preview: Linear fit equation: y = -5443.4x + 15.74 R 2 from fit: 0.992 Calculated boiling pt ( o C): 72.8 Calculated Hv (kJ/mol): 45.258 Actual boiling pt ( o C): 78.3 Actual Hv (kJ/mol): 40.5 %error in boiling pt: 7.02% %error in Hv: 11.75% Post-lab questions 1. Tap water can be made to boil vigorously at room temperature. Explain how this might be done in the laboratory and why would it work? By decreasing pressure, boiling point will be decreased, and then tap water can be made to boil vigorously. 2. Suppose your ethanol sample contained a significant amount of dissolved air. Would you expect this to affect your measured value of Hv? Explain why or why not. Yes. If there is a significant amount of dissolved air, vapor pressure will less than the real value, since the measured value need to subtract the air’s pressure. If there is something wrong with the vapor pressure and the value of ln(p), Hv will not be correct....
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