Unformatted text preview: lim n →∞ n1 X i =0 2 πf (¯ x i ) p 1 + ( f ± ( t i )) 2 Δ x = Z b a 2 πf ( x ) p 1 + ( f ± ( x )) 2 dx is the surface area we seek. x i ¯ x i x i +1 ............................................... ( x i , f ( x i )) ( x i +1 , f ( x i +1 )) Figure 9.24 One subinterval. EXAMPLE 9.38 We compute the surface area of a sphere of radius r . The sphere can be obtained by rotating the graph of f ( x ) = p r 2x 2 about the xaxis. The derivative...
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 Spring '07
 JonathanRogawski
 Math, Calculus, Cone

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