Unformatted text preview: k (1 + x + x 2 + x 3 + Â·Â·Â· + x n )1k (1 + x + x 2 + x 3 + Â·Â·Â· + x n1 + x n ) x = k (1 + x + x 2 + x 3 + Â·Â·Â· + x nxx 2x 3 Â·Â·Â· x nx n +1 ) = k (1x n +1 ) so s n (1x ) = k (1x n +1 ) s n = k 1x n +1 1x . If  x  < 1, lim n â†’âˆž x n = 0 so lim n â†’âˆž s n = lim n â†’âˆž k 1x n +1 1x = k 1 1x ....
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 Spring '07
 JonathanRogawski
 Math, Calculus, Sn, Xn

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