CJ 301 Asm 6 second page

CJ 301 Asm 6 second page - (3 points Mean = 6.5 tmes per...

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4.19-9.99 1. Construct an 80% confidence interval around the estimated mean number of alcohol problems obtained from this sample (question 1). (4 points) N=18 Mean:7.09 Standard Deviation:6.11 80%/2= 40% Area: .1554 80% CI =7.09+-.40(6.11/Square root 18-1) =7.09+-.40(6.11/square root 17) =7.09+-.40(6.11/4.11) =7.09+-.40(1.48) =7.09+ .59=7.68 =7.09-.59=6.5 CI=6.5-7.68 2. A hypothetical study concerned with estimating the amount of marijuana use per year among a teenage population obtained a sample of 110 high (n=110) school students. With the following sample statistics, construct a 75% confidence interval around the mean number of times this sample used marijuana in a given 1-year period:
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Unformatted text preview: (3 points) Mean = 6.5 tmes per year sd= 4.2 tmes per year n = 110 75%/2 =37.5% Area=.3749 (.3750) zscore=1.15 75% CI =6.5+-1.15 (4.2/Square rooT 110-1) =6.5+-1.15 (4.2/Square rooT 109) =6.5+-1.15 (4.2/10.44) =6.5+-1.15 (.40) =6.5+-.46 =6.5+.46=6.96 =6.5-.46=6.04 75% CI 6.04-6.96 4. Using The daTa in queston #3, construct a 90% confdence interval around The mean number of tmes marijuana was used. (4 points) 90%/2= 45% Area:.45 z: 1.65 90%CI 6.5+-1.65(4.2/square root 110-1) 6.5+-1.65(4.2/109) 6.5+-1.65(4.2/10.44) 6.5+-1.65(.40) 6.5+-.66 6.5+.66=7.16 6.5-.66=5.84 90% CI 5.84-7.16...
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