cj 301 asm midterm page 5

# cj 301 asm midterm page 5 - incidents of mass murder...

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Calculator: invnorm on the calculator with a percentile of 95% mean 50 and sd 10 it tells me that you have to score at least a 64.5 to be in the top 5 percent of scores. Yes he would be accepted 10. Assume you have administered a test to random sample of N- sample=100 workers at your company. The test is purported to have a population standard deviation = 8.0 The test results reveal a sample MEAN=50. (4 points) Question: What i s the formula to calculate the CI (confidence interval) in this example? – you don’t need to calculate the CI, just show the formula. 50+-1.96 * ( 8/square root of 100) 11. A sample of 200 (N=200)

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Unformatted text preview: incidents of mass murder reveals that the mean number of vicTms per incident is 50 , with a standard deviaTon of 30. Sample mean=50 S= 30 N=200 Calculate the 85% conFdence interval (CI) for number of vicTms per mass murder incident and interpret your results. (5 points) 46.95-53.05 vicTms 1 12.If a variable has two modes it is called: (2 points) a) unimodal b) skewed mulTmodal c) bimodal Answer:___Bimodal_________ 13.A university professor was interested in idenTfying leF-handed students from all of the six introductory-level psychology classes in the Good luck! 2...
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