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problem26_15 - 26.15 a I R 120 V(400 800 0.100 A b P400 I 2...

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26.15: a) . A 100 . 0 ) 800 400 ( V 120 = + = = R ε I b) = = = = = = ) 800 ( ) A 100 . 0 ( ; W 0 . 4 ) 400 ( ) A 100 . 0 ( 2 2 800 2 2 400 R I P R I P . W 12 W 8 W 4 W 0 . 8 = + = total P c) When in parallel, the equivalent resistance becomes: . A 449 . 0 267 V 120 267 800 1 400 1 eq total 1 eq = = = = + = - R ε I R . A 150 . 0 ) A 449 . 0 ( 800 400 400 ; A 30 . 0 ) A 449 . 0 ( 800 400 800 800 400 = + = = + = I I d) W 18 ) 800 ( ) A 15 . 0 ( ; W 36 ) 400 ( ) A 30 . 0 ( 2 2 800 2 2 400 = = = = = = R I P R I P . W 54 W 18 W 36 = + = total P e) The 800
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