problem26_20

problem26_20 - ( 29 ( 29 ( 29 ( 29 . V . 7 00 . 2 00 . 1 A...

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26.20: From the given currents in the diagram, the current through the middle branch of the circuit must be 1.00 A (the difference between 2.00 A and 1.00 A). We now use Kirchoff’s Rules, passing counterclockwise around the top loop: ( 29 ( 29 ( 29 V. 18.0 0 Ω 1.00 Ω 4.00 A 1.00 Ω 1.00 Ω 6.00 A) (1.00 V 20.0 1 1 = = - + + + - ε ε Now traveling around the external loop of the circuit:
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Unformatted text preview: ( 29 ( 29 ( 29 ( 29 . V . 7 00 . 2 00 . 1 A 00 . 2 00 . 1 00 . 6 A 00 . 1 V . 20 2 2 = =- + - + - And ( 29 ( 29 . V . 13 so , V . 13 V . 18 00 . 1 00 . 4 A 00 . 1 V-= + = + + -= ba ab V...
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